Melbourne, July 17: India’s Harinder Pal Sandhu on Sunday registered a comprehensive win over Australian Rex Hedrick in the summit clash of Victoria Open squash and bagged the title. Notably, Harinder Pal Sandhu defeated top-seed Rex Hedrick by 12-14, 11-3, 11-4, 11-7 in a 77-minute final of Victoria Open squash in Melbourne.
Sandhu, who had reached the final without dropping a game, ran into an opponent, who was ready for a long battle. Harinder stormed back from a one-game deficit to upset the top seed Rex Hedrick of Australia. The first game saw long rallies and Hedrick held his nerve to win it on extra points as the two mixed caution with aggression.
Third-seeded Sandhu, who had won the South Australian Open last week, stepped up to win the second game 11-3 using an attacking game to keep his rival at bay. The third game also followed a similar pattern as Sandhu romped home 11-4.
The 28-year-old Indian carried the momentum into the fourth game and stayed ahead to win it 11-7. It was his fourth title of the year. He had beaten Piedro Schweertman of the Netherlands yesterday to reach the final.
This is the fourth title in a row on the professional circuit for the 28-year-old Chandigarh-born player, who has been a former national champion. This win also helped extend his winning streak to a stunning 17 matches now. This is Sandhu’s ninth PSA title overall. His last loss came in the quarter-finals of the Asian Championships held at home in Chennai in April.